F(x)=3x^2-12x-36

Solution for F(x)=3x^2-12x-36 equation:

(F)=3F^2-12F-36

We move all terms to the left:

(F)-(3F^2-12F-36)=0

We get rid of parentheses

-3F^2+F+12F+36=0

We add all the numbers together, and all the variables

-3F^2+13F+36=0

a = -3; b = 13; c = +36;
Δ = b2-4ac
Δ = 132-4·(-3)·36
Δ = 601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{601}}{2*-3}=\frac{-13-\sqrt{601}}{-6}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{601}}{2*-3}=\frac{-13+\sqrt{601}}{-6}
$